![]() ![]() The movement is either 0 mm or 100 mm.Īfter, clicking the paste, you need to delete the 3/2 way DCV, NC push button since it is not part on the second control circuit. By which the primary double-acting cylinder depending on the secondary double-acting cylinder's position, as sense by the limit switch. This is for the configuration of the second double-acting cylinder control circuit.ĭiscussion: Since the aim of the project is to design and simulate an automatic sequential motion for pneumatic double-acting cylinder, we need two set-up of control circuit for the system. (Duplicate the set-up made) In this part, we will copy the whole set-up created so far. Step 5: Creating the secondary control circuit. But, first, double click the 3/2 way DCV so that a dialog box will appear.Ĭonfigure all exhaust terminal as designated to terminal no. Follow the steps as indicated in the figure below. Do this step for all equipment, as shown in figure.Ĭonfiguring the 3/2 way DCV. Click first the terminal designation, hold then drag to the next terminal. Double click the 5/2 way DCV first before a dialog box appears.Ĭonnecting the 5/2 way DCV to the 3/2 way DCV. Follow the procedure as indicated in the figure below. To finish the configuration of the 5/2 way DCV, put the terminal designation number for the pneumatic actuation of the 5.2 way DCV. ![]() The result will look the same with the figure below. Step 4: Configure and connect equipment Configuring the 5/2 way directional control valve, simply follow the steps as indicated in the figure.Īfter following the procedure as indicated in the figure above. And, arrange the materials according to the picture shown below. After clicking the material, you simply drag it to the new project workplace.ĭo it until you selected all the necessary listed materials. Step 3: Select the Materials to be used To select the materials to be used, you click the symbol of material as indicated in the left pane in the worksheet. Select NEW or you can directly use shortcut key CRTL + N. Step 2: Create a NEW Project Locate FILE on the menu bar, and a drop-down option appears. So, both cylinder will not retract at the same time, but the double-acting cylinder #2 will be depend on the position of double-acting cylinder #1, either at 0 mm or at 100 mm (full retraction). Our desired output will be an automatic sequential/ alternating retraction of piston in two pneumatic double-acting cylinder. Sensor S2 is deactivated once B travels and S1 is activated when initial position is reached.Let’s start with the materials and software that we will be using in this topic.ģ/2 way directional control valve, normally close push button, spring-returnedģ/2 way directional control valve, normally open limit switch, with roller, spring-returnedĥ/2 way directional control valve, pneumatically actuated. When S3 is actuated, memory M4 is set and Memory flag M3 is reset. Sensor S4 is deactivated once B travels and S3 is activated when initial position is reached. When S4 is actuated, memory M3 is set and Memory flag M2 is reset. Sensor S3 is deactivated once B travels and S4 is activated when end position is reached. When S2 is actuated, memory M2 is set and Memory flag M1 is reset. Sensor S1 is deactivated once A travels and S2 is activated when end position is reached. Pressing PB1 sets Memory flag M1 and resets Memory flag M4. Initially S1 and S3 are actuated and generate outputs. Pressing PB2 causes the last memory state M4 to set and all other memory flags M1, M2 and M3 to reset. In this sequence circuit, PB2 is used to initiate the program. Draw the pneumatic circuit, PLC wiring diagram and ladder diagram to implement this task. Cylinder is returned by pressing push button PB2. Pneumatic cylinder is advanced by pressing push buttons PB1. If any one of PB1 and PB2 is pressed, then corresponding bit addresses turns to 0, since I1 and I2 are in series, if any of them turns to 0 state, there will not be any output at 01 and thus solenoid is de-energised and returns back.Įxample 2 : Double acting cylinder is used to perform forward and return motion. Output at the coil 01 operated the solenoid coil and cylinder moves forward to do the required operation. When the push buttons PB1 and PB2 are pressed simultaneously, the addresses I1 and I 2 turn to state 1 from state 0, as a result power flows through the coil and there will be output at coil 01. I1 and I2 are connected in series in ladder diagram to realize this AND logic function. ![]() As shown in the PLC wiring diaram, The push buttons PB1 and PB2 are connected at memory address I1 and I2.
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